2x^2-18/4x+12

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Solution for 2x^2-18/4x+12 equation: 


x in (-oo:+oo)

2*x^2-((18/4)*x)+12 = 0

2*x^2+(-9/2)*x+12 = 0

2*x^2-9/2*x+12 = 0

DELTA = (-9/2)^2-(2*4*12)

DELTA = -303/4

DELTA < 0

x belongs to the empty set

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